i tell you sir, it does not. haha.
combinations (order does not matter a.k.a king of spades-ace of spades is equal to ace of spades-king of spades)-
nCx (n choose x)
n!/(x!*(n-x)!)
so (55*54*...)/((53*52*51..)(2*1))
permutations (order does matter a.k.a king of spades-ace of spades is NOT equal to ace of spades-king of spades)
nPx
simply. n!/(n-x)!
7 of Spades, Ace of Diamonds
Six of Hearts, 9 of Clubs
4 of Hearts, Queen of Diamonds
Mitch